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ap distance in cM can be estimated:Question 7Answera.by the number of parental offspring observed in a testcross divided the total number of  offspringb.by the number of recombinant offspring observed in a testcross divided by 2c.by the number of recombinant offspring observed in a testcross divided the total number of offspringd.by the number of parental offspring observed in a testcross divided the number of recombinant offspringe.by the number of recombinant offspring observed in a testcross divided the number of parental offspring

Question

ap distance in cM can be estimated:Question 7Answera.by the number of parental offspring observed in a testcross divided the total number of  offspringb.by the number of recombinant offspring observed in a testcross divided by 2c.by the number of recombinant offspring observed in a testcross divided the total number of offspringd.by the number of parental offspring observed in a testcross divided the number of recombinant offspringe.by the number of recombinant offspring observed in a testcross divided the number of parental offspring

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Solution

The distance between two genes in centimorgans (cM) can be estimated by the number of recombinant offspring observed in a testcross divided by the total number of offspring. So, the correct answer is option c.

Here's the step-by-step process:

  1. Perform a testcross. This is a cross between an individual with an unknown genotype and an individual that is homozygous recessive for the trait in question.

  2. Count the number of recombinant offspring. These are the offspring that have a different combination of traits than either parent.

  3. Count the total number of offspring.

  4. Divide the number of recombinant offspring by the total number of offspring.

  5. Multiply the result by 100 to get the distance in centimorgans (cM).

This method is based on the principle that the frequency of recombination between two genes is proportional to the distance between them. The greater the distance, the more likely that recombination will occur.

This problem has been solved

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