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11. The prefix form of A-B/ (C * D ^ E) is?a) -A/B*C^DEb) -A/BC*^DEc) -ABCD*^DEd) -/*^ACBDE

Question

  1. The prefix form of A-B/ (C * D ^ E) is?a) -A/BC^DEb) -A/BC^DEc) -ABCD*^DEd) -/*^ACBDE
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Solution 1

The prefix form of A-B/ (C * D ^ E) is -/^ACBDE. So, the correct answer is d) -/^ACBDE.

Here's the step-by-step conversion:

  1. Start with the infix expression: A-B/ (C * D ^ E)
  2. Apply the precedence of operators. The precedence order is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right). So, the expression becomes: A-(B/ (C * (D ^ E)))
  3. Convert the expression to prefix: -A/BC*^DE
  4. Adjust the operands to match the prefix notation: -/*^ACBDE

So, the prefix form of the given infix expression is -/*^ACBDE.

This problem has been solved

Solution 2

The prefix form of A-B/ (C * D ^ E) is -/*A B ^C D E. So, the correct answer is d) -/^ACBDE.

Here's the step-by-step conversion:

  1. Start with the infix notation: A - B / (C * D ^ E)
  2. Identify the highest precedence operator. In this case, it's the exponentiation operator (^).
  3. Move the operator (^) before the operands (D and E): A - B / (^DE * C)
  4. Repeat the process for the next highest precedence operator, which is multiplication (): A - B / (^DEC)
  5. Repeat the process for the next highest precedence operator, which is division (/): A - (/B*^DEC)
  6. Repeat the process for the next highest precedence operator, which is subtraction (-): -A/(*^DECB)

So, the prefix notation of A - B / (C * D ^ E) is -/*A B ^C *D E.

This problem has been solved

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