A pulling force of 7 N to the left , a pushing force of 4 N to the right and a pulling force of 4 N to the right acts on a box that is on a frictionless surface. What is the net force acting on the box?
Question
A pulling force of 7 N to the left , a pushing force of 4 N to the right and a pulling force of 4 N to the right acts on a box that is on a frictionless surface. What is the net force acting on the box?
Solution
First, let's identify the forces acting on the box.
- A pulling force of 7 N to the left.
- A pushing force of 4 N to the right.
- A pulling force of 4 N to the right.
Next, we need to determine the net force. The net force is the vector sum of all the forces. In this case, we can consider forces to the right as positive and forces to the left as negative.
So, the net force (F_net) can be calculated as follows:
F_net = Sum of all forces = -7 N (to the left) + 4 N (to the right) + 4 N (to the right) = -7 N + 4 N + 4 N = 1 N to the right
So, the net force acting on the box is 1 N to the right.
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