This problem is asking you to write a program that prints a hollow diamond pattern using asterisks ('*'). The program should take multiple test cases as input. Each test case is a single odd integer N, which represents the size of the diamond.

Here is a step-by-step guide on how to solve this problem:

1. First, you need to understand the pattern of the hollow diamond. For a diamond of size N, the first line will have (N-1)/2 spaces followed by an asterisk. Each subsequent line until the middle of the diamond will have one less space and two more asterisks, forming the top half of the diamond.

2. The middle line of the diamond will have N asterisks.

3. After the middle line, the pattern reverses. Each line will have one more space and two less asterisks, forming the bottom half of the diamond.

4. To implement this in a program, you can use nested loops. The outer loop will iterate over each line of the diamond. The inner loops will print the spaces and asterisks for each line.

5. For each test case, you should print the test case number followed by the diamond pattern.

6. Make sure to handle the constraints: the number of test cases T is between 1 and 100, and the size of the diamond N is an odd number between 3 and 201.

Here is a Python solution for the problem:

```python
T = int(input())
for t in range(T):
N = int(input())
print('Case #{}:'.format(t+1))
for i in range(N):
for j in range(N):
if j == N//2 or i == N//2 or j == N//2 + i or j == N//2 - i or i == N//2 + j or i == N//2 - j:
print('*', end='')
else:
print(' ', end='')
print()
```

This solution uses the properties of the diamond pattern to determine whether to print an asterisk or a space at each position. The conditions in the if statement check if the current position is on one of the lines that form the diamond.

Question

This problem is asking you to write a program that prints a hollow diamond pattern using asterisks ('*'). The program should take multiple test cases as input. Each test case is a single odd integer N, which represents the size of the diamond.

Here is a step-by-step guide on how to solve this problem:

1. First, you need to understand the pattern of the hollow diamond. For a diamond of size N, the first line will have (N-1)/2 spaces followed by an asterisk. Each subsequent line until the middle of the diamond will have one less space and two more asterisks, forming the top half of the diamond.

2. The middle line of the diamond will have N asterisks.

3. After the middle line, the pattern reverses. Each line will have one more space and two less asterisks, forming the bottom half of the diamond.

4. To implement this in a program, you can use nested loops. The outer loop will iterate over each line of the diamond. The inner loops will print the spaces and asterisks for each line.

5. For each test case, you should print the test case number followed by the diamond pattern.

6. Make sure to handle the constraints: the number of test cases T is between 1 and 100, and the size of the diamond N is an odd number between 3 and 201.

Here is a Python solution for the problem:

```python
T = int(input())
for t in range(T):
    N = int(input())
    print('Case #{}:'.format(t+1))
    for i in range(N):
        for j in range(N):
            if j == N//2 or i == N//2 or j == N//2 + i or j == N//2 - i or i == N//2 + j or i == N//2 - j:
                print('*', end='')
            else:
                print(' ', end='')
        print()
```

This solution uses the properties of the diamond pattern to determine whether to print an asterisk or a space at each position. The conditions in the if statement check if the current position is on one of the lines that form the diamond.

Knowee AI · Accepted Answer