To solve this problem, we will use the concept of combinations from combinatorics.

Step 1: We need to select 2 trainers out of 3. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and '!' denotes factorial.

So, the number of ways to choose 2 trainers out of 3 is C(3, 2) = 3! / [2!(3-2)!] = 3.

Step 2: We need to select 3 Research Associates out of 6. Using the same combination formula, the number of ways to do this is C(6, 3) = 6! / [3!(6-3)!] = 20.

Step 3: To find the total number of ways to form the committee, we multiply the results from step 1 and step 2 because for each way of choosing the trainers, there are multiple ways of choosing the Research Associates.

So, the total number of ways to form the committee is 3 * 20 = 60.

Question

To solve this problem, we will use the concept of combinations from combinatorics.

Step 1: We need to select 2 trainers out of 3. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and '!' denotes factorial.

So, the number of ways to choose 2 trainers out of 3 is C(3, 2) = 3! / [2!(3-2)!] = 3.

Step 2: We need to select 3 Research Associates out of 6. Using the same combination formula, the number of ways to do this is C(6, 3) = 6! / [3!(6-3)!] = 20.

Step 3: To find the total number of ways to form the committee, we multiply the results from step 1 and step 2 because for each way of choosing the trainers, there are multiple ways of choosing the Research Associates.

So, the total number of ways to form the committee is 3 * 20 = 60.

Knowee AI · Accepted Answer

To solve this problem, we will use the concept of combinations from combinatorics.

Step 1: We need to select 2 trainers out of 3. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and '!' denotes factorial.

So, the number of ways to choose 2 trainers out of 3 is C(3, 2) = 3! / [2!(3-2)!] = 3.

Step 2: We need to select 3 Research Associates out of 6. Using the same combination formula, the number of ways to do this is C(6, 3) = 6! / [3!(6-3)!] = 20.

Step 3: To find the total number of ways to form the committee, we multiply the results from step 1 and step 2 because for each way of choosing the trainers, there are multiple ways of choosing the Research Associates.

So, the total number of ways to form the committee is 3 * 20 = 60.

A committee of 5 members is going to be formed from 3 Trainers, Four Professors and 6 Research Associates. How many ways can they be selected, if- in committee, there are 2 Trainers and three Research Associates?

Question

Solution

Similar Questions

Upgrade your grade with Knowee