The incorrect statement is: "In a given period of time, car B will travel four times as far as car A."

Here's why:

1. "Both graphs will start from the origin (0, 0)" - This is correct. Since both cars start from rest and at the same time, their velocity-time graphs will start from the origin.

2. "The velocity-time graph for the motion of car B will be twice as steep as that of car A" - This is correct. The steepness or gradient of a velocity-time graph represents acceleration. Since car B's acceleration is twice that of car A, its graph will be twice as steep.

3. "The gradient of the velocity-time graph for the motion of car A will be half that of the velocity-time graph for car B" - This is correct. It's essentially the same statement as the previous one, just phrased differently.

4. "In a given period of time, car B will travel four times as far as car A" - This is incorrect. While car B does accelerate twice as fast as car A, it doesn't mean it will travel four times as far. The distance travelled under uniform acceleration is given by the equation d = 0.5*a*t^2, where d is distance, a is acceleration, and t is time. If we compare the distances travelled by cars A and B in the same time period, we get d

Question

The incorrect statement is: "In a given period of time, car B will travel four times as far as car A."

Here's why:

1. "Both graphs will start from the origin (0, 0)" - This is correct. Since both cars start from rest and at the same time, their velocity-time graphs will start from the origin.

2. "The velocity-time graph for the motion of car B will be twice as steep as that of car A" - This is correct. The steepness or gradient of a velocity-time graph represents acceleration. Since car B's acceleration is twice that of car A, its graph will be twice as steep.

3. "The gradient of the velocity-time graph for the motion of car A will be half that of the velocity-time graph for car B" - This is correct. It's essentially the same statement as the previous one, just phrased differently.

4. "In a given period of time, car B will travel four times as far as car A" - This is incorrect. While car B does accelerate twice as fast as car A, it doesn't mean it will travel four times as far. The distance travelled under uniform acceleration is given by the equation d = 0.5*a*t^2, where d is distance, a is acceleration, and t is time. If we compare the distances travelled by cars A and B in the same time period, we get d

Knowee AI · Accepted Answer

The incorrect statement is: "In a given period of time, car B will travel four times as far as car A."

Here's why:

1. "Both graphs will start from the origin (0, 0)" - This is correct. Since both cars start from rest and at the same time, their velocity-time graphs will start from the origin.

2. "The velocity-time graph for the motion of car B will be twice as steep as that of car A" - This is correct. The steepness or gradient of a velocity-time graph represents acceleration. Since car B's acceleration is twice that of car A, its graph will be twice as steep.

3. "The gradient of the velocity-time graph for the motion of car A will be half that of the velocity-time graph for car B" - This is correct. It's essentially the same statement as the previous one, just phrased differently.

4. "In a given period of time, car B will travel four times as far as car A" - This is incorrect. While car B does accelerate twice as fast as car A, it doesn't mean it will travel four times as far. The distance travelled under uniform acceleration is given by the equation d = 0.5*a*t^2, where d is distance, a is acceleration, and t is time. If we compare the distances travelled by cars A and B in the same time period, we get d

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