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f A = 3 -1 ,2 1Show that A2 - 4 A + 5 I2 = 0.

Question

f A = 3 -1 ,2 1Show that A2 - 4 A + 5 I2 = 0.

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Solution

Sure, let's solve this step by step.

First, let's define the matrix A and the identity matrix I:

A = [3 -1] [2 1]

I = [1 0] [0 1]

Next, we calculate A^2, which is the matrix A multiplied by itself:

A^2 = A * A = [3 -1] * [3 -1] [2 1] [2 1] = [(33 + -12) (3*-1 + -11)] [(23 + 12) (2-1 + 1*1)] = [7 -4] [8 0]

Then, we calculate 4A:

4A = 4 * A = 4 * [3 -1] [2 1] = [12 -4] [8 4]

Next, we calculate 5I:

5I = 5 * I = 5 * [1 0] [0 1] = [5 0] [0 5]

Finally, we calculate A^2 - 4A + 5I:

A^2 - 4A + 5I = [7 -4] - [12 -4] + [5 0] [8 0] [8 4] [0 5] = [-5 0] [0 5]

So, A^2 - 4A + 5I = 0, as required.

This problem has been solved

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