A container with two gases, helium and argon, is 92.62% by volume helium. Calculate the partial pressure of argon if the total pressure inside the container is 4 atm.
Question
A container with two gases, helium and argon, is 92.62% by volume helium. Calculate the partial pressure of argon if the total pressure inside the container is 4 atm.
Solution
Sure, here are the steps to solve this problem:
Step 1: Determine the volume percentage of argon in the container. Since the container is 92.62% helium, the remaining percentage must be argon. So, 100% - 92.62% = 7.38% argon.
Step 2: Convert this percentage to a decimal by dividing by 100. So, 7.38% = 0.0738 in decimal form.
Step 3: The partial pressure of a gas in a mixture is given by the total pressure multiplied by the volume fraction (or mole fraction) of the gas. So, the partial pressure of argon = total pressure * volume fraction of argon = 4 atm * 0.0738 = 0.2952 atm.
So, the partial pressure of argon in the container is approximately 0.2952 atm.
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