Which of the following sequences can not be the degree sequence of any graph when the degree sequence of a simple graph is the sequence of the degrees of the nodes in the graph in decreasing order ?I. 7, 6, 5, 4, 4, 3, 2, 1II. 6, 6, 6, 6, 3, 3, 2, 2III. 7, 6, 6, 4, 4, 3, 2, 2IV. 8, 7, 7, 6, 4, 2, 1, 1 OptionsII and IIIII and IVI and IIIII Only
Question
Which of the following sequences can not be the degree sequence of any graph when the degree sequence of a simple graph is the sequence of the degrees of the nodes in the graph in decreasing order ?I. 7, 6, 5, 4, 4, 3, 2, 1II. 6, 6, 6, 6, 3, 3, 2, 2III. 7, 6, 6, 4, 4, 3, 2, 2IV. 8, 7, 7, 6, 4, 2, 1, 1 OptionsII and IIIII and IVI and IIIII Only
Solution 1
The degree sequence of a simple graph is a sequence of the degrees of the nodes in the graph in decreasing order. A sequence can be the degree sequence of a graph if and only if it satisfies the Handshaking Lemma and the Havel-Hakimi theorem.
The Handshaking Lemma states that the sum of the degrees of all the vertices in a graph is equal to twice the number of edges. This means that the sum of the degrees in the sequence must be an even number.
The Havel-Hakimi theorem is a method to check if a degree sequence is graphical (i.e., if there exists a graph with that degree sequence). The theorem works as follows:
- Sort the sequence in non-increasing order.
- If the sequence contains any negative numbers, it is not graphical.
- If the sequence is all zeros, it is graphical.
- Otherwise, remove the first number (n) from the sequence, and subtract 1 from the next n numbers. Go back to step 1.
Let's apply these rules to the given sequences:
I. 7, 6, 5, 4, 4, 3, 2, 1: The sum is 32, which is even. Applying the Havel-Hakimi theorem, we get 5, 4, 3, 3, 2, 1, 1, which is still graphical. So, this sequence is graphical.
II. 6, 6, 6, 6, 3, 3, 2, 2: The sum is 34, which is even. Applying the Havel-Hakimi theorem, we get 5, 5, 5, 2, 2, 1, 1, which is not graphical. So, this sequence is not graphical.
III. 7, 6, 6, 4, 4, 3, 2, 2: The sum is 34, which is even. Applying the Havel-Hakimi theorem, we get 5, 5, 3, 3, 2, 1, 1, which is still graphical. So, this sequence is graphical.
IV. 8, 7, 7, 6, 4, 2, 1, 1: The sum is 36, which is even. However, the first number is 8, which is greater than the number of remaining numbers in the sequence (7). So, this sequence is not graphical.
Therefore, the sequences that cannot be the degree sequence of any graph are II and IV.
Solution 2
The degree sequence of a simple graph is a sequence of the degrees of the nodes in the graph in decreasing order. A sequence can be the degree sequence of a graph if and only if it satisfies the Handshaking Lemma and the Havel-Hakimi theorem.
The Handshaking Lemma states that the sum of the degrees of all the vertices in a graph is twice the number of edges. This means that the sum of the degrees in the sequence must be an even number.
The Havel-Hakimi theorem provides a method to check if a sequence can be the degree sequence of a simple graph. It works by repeatedly removing the highest degree and reducing the next highest degrees by one until either all degrees are zero (in which case the sequence is graphical) or it is impossible to continue (in which case the sequence is not graphical).
Let's apply these rules to the given sequences:
I. 7, 6, 5, 4, 4, 3, 2, 1: The sum of the degrees is 32, which is even. Applying the Havel-Hakimi theorem, we get the following sequences: 5, 4, 3, 3, 2, 1, 1,
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