The ratio of the present ages of two boys is 3 : 4. After 3 years, the ratio of their ages is equal to will be 4 : 5.The ratio of their ages after 21 years will be?Options10 : 1117 : 1914 : 1711 : 12
Question
The ratio of the present ages of two boys is 3 : 4. After 3 years, the ratio of their ages is equal to will be 4 : 5.The ratio of their ages after 21 years will be?Options10 : 1117 : 1914 : 1711 : 12
Solution
Let's solve this step by step:
Step 1: Let's assume the present ages of the two boys are 3x and 4x.
Step 2: According to the problem, after 3 years, the ratio of their ages will be 4:5. So, we can set up the equation as follows:
(3x + 3) / (4x + 3) = 4/5
Step 3: Cross-multiply to solve for x:
5*(3x + 3) = 4*(4x + 3)
15x + 15 = 16x + 12
Step 4: Simplify the equation to find the value of x:
x = 15 - 12 = 3
Step 5: Now that we have the value of x, we can find the present ages of the boys:
First boy's age = 3x = 33 = 9 years Second boy's age = 4x = 43 = 12 years
Step 6: We are asked to find the ratio of their ages after 21 years. So, their ages after 21 years will be:
First boy's age = 9 + 21 = 30 years Second boy's age = 12 + 21 = 33 years
Step 7: Therefore, the ratio of their ages after 21 years will be 30:33, which simplifies to 10:11.
So, the correct option is 10:11.
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