This problem can be solved using dynamic programming. Here are the steps:

1. Create an array dp of the same length as nums, where dp[i] is the maximum amount of money you can rob from the first i houses. Initialize dp[0] to nums[0] and dp[1] to max(nums[0], nums[1]).

2. For each house from the third one (i = 2) to the last one, calculate the maximum amount of money you can rob from the first i houses. This is either the amount of money you can rob from the first i - 1 houses (which means you don't rob the current house), or the amount of money you can rob from the first i - 2 houses plus the money in the current house (which means you do rob the current house). So dp[i] = max(dp[i - 1], dp[i - 2] + nums[i]).

3. The maximum amount of money you can rob from all the houses is the maximum amount of money you can rob from the first n houses, which is dp[n - 1], where n is the number of houses.

Here is the Python code for this solution:

```python
def rob(nums):
if not nums:
return 0
if len(nums) == 1:
return nums[0]
dp = [0] * len(nums)
dp[0] = nums[0]
dp[1] = max(nums[0], nums[1])
for i in range(2, len(nums)):
dp[i] = max(dp[i - 1], dp[i - 2] + nums[i])
return dp[-1]
```

You can call this function with the input array to get the maximum amount of money you can rob. For example, `rob([1,2,3,1])` returns `4`.

Question

This problem can be solved using dynamic programming. Here are the steps:

1. Create an array dp of the same length as nums, where dp[i] is the maximum amount of money you can rob from the first i houses. Initialize dp[0] to nums[0] and dp[1] to max(nums[0], nums[1]).

2. For each house from the third one (i = 2) to the last one, calculate the maximum amount of money you can rob from the first i houses. This is either the amount of money you can rob from the first i - 1 houses (which means you don't rob the current house), or the amount of money you can rob from the first i - 2 houses plus the money in the current house (which means you do rob the current house). So dp[i] = max(dp[i - 1], dp[i - 2] + nums[i]).

3. The maximum amount of money you can rob from all the houses is the maximum amount of money you can rob from the first n houses, which is dp[n - 1], where n is the number of houses.

Here is the Python code for this solution:

```python
def rob(nums):
    if not nums:
        return 0
    if len(nums) == 1:
        return nums[0]
    dp = [0] * len(nums)
    dp[0] = nums[0]
    dp[1] = max(nums[0], nums[1])
    for i in range(2, len(nums)):
        dp[i] = max(dp[i - 1], dp[i - 2] + nums[i])
    return dp[-1]
```

You can call this function with the input array to get the maximum amount of money you can rob. For example, `rob([1,2,3,1])` returns `4`.

Knowee AI · Accepted Answer

This problem can be solved using dynamic programming. Here are the steps:

1. Create an array dp of the same length as nums, where dp[i] is the maximum amount of money you can rob from the first i houses. Initialize dp[0] to nums[0] and dp[1] to max(nums[0], nums[1]).

2. For each house from the third one (i = 2) to the last one, calculate the maximum amount of money you can rob from the first i houses. This is either the amount of money you can rob from the first i - 1 houses (which means you don't rob the current house), or the amount of money you can rob from the first i - 2 houses plus the money in the current house (which means you do rob the current house). So dp[i] = max(dp[i - 1], dp[i - 2] + nums[i]).

3. The maximum amount of money you can rob from all the houses is the maximum amount of money you can rob from the first n houses, which is dp[n - 1], where n is the number of houses.

Here is the Python code for this solution:

```python
def rob(nums):
    if not nums:
        return 0
    if len(nums) == 1:
        return nums[0]
    dp = [0] * len(nums)
    dp[0] = nums[0]
    dp[1] = max(nums[0], nums[1])
    for i in range(2, len(nums)):
        dp[i] = max(dp[i - 1], dp[i - 2] + nums[i])
    return dp[-1]
```

You can call this function with the input array to get the maximum amount of money you can rob. For example, `rob([1,2,3,1])` returns `4`.

Question

Solution

Similar Questions

Upgrade your grade with Knowee