The conic represented by x=2(cost+sint),y=5(cost−sint) isa circlea parabolaan ellipsea hyperbola
Question
The conic represented by x=2(cost+sint),y=5(cost−sint) isa circlea parabolaan ellipsea hyperbola
Solution
The given parametric equations are x = 2(cos(t) + sin(t)) and y = 5(cos(t) - sin(t)).
To identify the conic section represented by these equations, we can eliminate the parameter t by using the Pythagorean identity sin^2(t) + cos^2(t) = 1.
First, we can express cos(t) and sin(t) in terms of x and y:
cos(t) = (x - y) / 7 and sin(t) = (x + y) / 7.
Then, we substitute these expressions into the Pythagorean identity:
[(x - y) / 7]^2 + [(x + y) / 7]^2 = 1.
Simplify this equation to get:
(x^2 - 2xy + y^2) / 49 + (x^2 + 2xy + y^2) / 49 = 1.
Combine like terms:
2x^2 + 2y^2 = 49.
Divide by 2:
x^2 + y^2 = 24.5.
This is the standard form of the equation of a circle with radius sqrt(24.5). So, the conic represented by the given parametric equations is a circle.
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