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What are the odds of not rolling a three on a standard six-sided die?

Question

What are the odds of not rolling a three on a standard six-sided die?

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Solution

Sure, let's break it down step by step:

  1. Identify the total number of possible outcomes: A standard six-sided die has 6 faces, so there are 6 possible outcomes when you roll the die.

  2. Identify the number of favorable outcomes: We are interested in the outcomes where we do not roll a three. The faces that are not three are 1, 2, 4, 5, and 6. So, there are 5 favorable outcomes.

  3. Calculate the probability of not rolling a three: The probability of an event is given by the number of favorable outcomes divided by the total number of possible outcomes. Therefore, the probability of not rolling a three is: Probability=Number of favorable outcomesTotal number of possible outcomes=56 \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{5}{6}

  4. Convert the probability to odds: The odds of an event are given by the ratio of the probability of the event occurring to the probability of the event not occurring. The probability of rolling a three is: Probability of rolling a three=16 \text{Probability of rolling a three} = \frac{1}{6} Therefore, the probability of not rolling a three is: Probability of not rolling a three=116=56 \text{Probability of not rolling a three} = 1 - \frac{1}{6} = \frac{5}{6} The odds are then: Odds=Probability of not rolling a threeProbability of rolling a three=5616=5 \text{Odds} = \frac{\text{Probability of not rolling a three}}{\text{Probability of rolling a three}} = \frac{\frac{5}{6}}{\frac{1}{6}} = 5

So, the odds of not rolling a three on a standard six-sided die are 5 to 1.

This problem has been solved

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