A female with AB blood type and a male with heterozygous blood type A. The genotype fractions for these children (overall) would be Question 7 options: 1/2 type A, 1/4 type AB, and 1/4 type B. 1/2 type A and 1/2 type B. 1/4 type A, 1/2 type AB, and 1/4 type B. 1/4 type A, ¼ type AB, and 1/2 type B. 1/2 type A and 1/2 type AB.
Question
A female with AB blood type and a male with heterozygous blood type A. The genotype fractions for these children (overall) would be
Question 7 options:
1/2 type A, 1/4 type AB, and 1/4 type B.
1/2 type A and 1/2 type B.
1/4 type A, 1/2 type AB, and 1/4 type B.
1/4 type A, ¼ type AB, and 1/2 type B.
1/2 type A and 1/2 type AB.
Solution
The blood type of a person is determined by two alleles (one from each parent). The possible alleles are A, B, and O.
The female has AB blood type, which means her genotype is AB.
The male has A blood type and is heterozygous, which means his genotype is AO.
The possible combinations for their children are:
- A from the mother and A from the father: genotype AA, blood type A.
- A from the mother and O from the father: genotype AO, blood type A.
- B from the mother and A from the father: genotype BA (or AB), blood type AB.
- B from the mother and O from the father: genotype BO, blood type B.
So, the genotype fractions for these children would be:
- 1/4 type A (AA)
- 1/4 type A (AO)
- 1/4 type AB (BA or AB)
- 1/4 type B (BO)
Therefore, the correct answer is: 1/2 type A, 1/4 type AB, and 1/4 type B.
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