When human red blood cells are placed in a solution of 0.10M NaCl and 0.15M glucose, it:
Question
When human red blood cells are placed in a solution of 0.10M NaCl and 0.15M glucose, it:
Solution
The behavior of red blood cells in a solution depends on the tonicity of the solution compared to the cells. Tonicity is a measure of the effective osmotic pressure gradient; it is dependent on the concentration of non-penetrating solutes such as NaCl and glucose.
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First, we need to determine the tonicity of the solution. The solution contains 0.10M NaCl and 0.15M glucose.
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Glucose is a penetrating solute, meaning it can cross the cell membrane. Therefore, it does not contribute to the tonicity of the solution.
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NaCl, however, is a non-penetrating solute. It cannot cross the cell membrane and therefore contributes to the tonicity of the solution.
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The concentration of NaCl in human blood is approximately 0.9%. This is equivalent to a 0.15M solution.
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Therefore, the solution of 0.10M NaCl is hypotonic compared to the red blood cells.
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When red blood cells are placed in a hypotonic solution, water will move into the cells by osmosis.
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This will cause the cells to swell and potentially burst, a process known as hemolysis.
So, when human red blood cells are placed in a solution of 0.10M NaCl and 0.15M glucose, they will undergo hemolysis.
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