The output of the given PHP code will be 10.

Here's the step by step explanation:

1. The PHP script starts with the declaration of two global variables $x and $y, with values 5 and 10 respectively.

2. Then a function named 'fun' is defined. Inside this function, a new local variable $y is declared. This local $y is not the same as the global $y.

3. The local $y is assigned the sum of the global variables $x and $y, which is 15. However, this operation does not affect the global $y variable.

4. The function 'fun' is called. This executes the code inside the function, but since the function does not return a value or change any global variables, this has no visible effect.

5. Finally, the global variable $y is echoed. Since the global $y was not changed by the function, its value is still 10, which is the output of the script.

Question

The output of the given PHP code will be 10.

Here's the step by step explanation:

1. The PHP script starts with the declaration of two global variables $x and $y, with values 5 and 10 respectively.

2. Then a function named 'fun' is defined. Inside this function, a new local variable $y is declared. This local $y is not the same as the global $y.

3. The local $y is assigned the sum of the global variables $x and $y, which is 15. However, this operation does not affect the global $y variable.

4. The function 'fun' is called. This executes the code inside the function, but since the function does not return a value or change any global variables, this has no visible effect.

5. Finally, the global variable $y is echoed. Since the global $y was not changed by the function, its value is still 10, which is the output of the script.

Knowee AI · Accepted Answer

The output of the given PHP code will be 10.

Here's the step by step explanation:

1. The PHP script starts with the declaration of two global variables $x and $y, with values 5 and 10 respectively.

2. Then a function named 'fun' is defined. Inside this function, a new local variable $y is declared. This local $y is not the same as the global $y.

3. The local $y is assigned the sum of the global variables $x and $y, which is 15. However, this operation does not affect the global $y variable.

4. The function 'fun' is called. This executes the code inside the function, but since the function does not return a value or change any global variables, this has no visible effect.

5. Finally, the global variable $y is echoed. Since the global $y was not changed by the function, its value is still 10, which is the output of the script.

What will be the output of the following PHP code?<?php$x = 5;$y = 10;function fun(){ $y = $GLOBALS['x'] + $GLOBALS['y'];} fun();echo $y;?>Group of answer choices10515error

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