Graph the function ๐(๐ฅ) = โ2๐ฅ2 + 2๐ฅ + 4 and its reciprocal on the same or separateaxes. Explain your thinking
Question
Graph the function ๐(๐ฅ) = โ2๐ฅ2 + 2๐ฅ + 4 and its reciprocal on the same or separateaxes. Explain your thinking
Solution
To graph the function ๐(๐ฅ) = โ2๐ฅ2 + 2๐ฅ + 4 and its reciprocal, follow these steps:
Step 1: Identify the type of function The given function is a quadratic function because it is in the form of ax^2 + bx + c.
Step 2: Identify the key features of the function The key features of a quadratic function are its vertex, axis of symmetry, and y-intercept.
For the given function, the vertex can be found using the formula -b/2a, which gives us x = 0.5. Substituting x = 0.5 into the function gives us the y-coordinate of the vertex, which is 3.5. So, the vertex is (0.5, 3.5).
The axis of symmetry is the vertical line passing through the vertex, which is x = 0.5.
The y-intercept is the value of the function when x = 0, which is 4.
Step 3: Sketch the function Plot the vertex, axis of symmetry, and y-intercept on a graph. Then, draw a parabola that passes through these points. The parabola opens downwards because the coefficient of x^2 is negative.
Step 4: Graph the reciprocal of the function The reciprocal of the function is 1/๐(๐ฅ) = 1/(-2๐ฅ2 + 2๐ฅ + 4). To graph this function, plot points for a range of x-values and connect them. Note that the reciprocal function will not be defined where the original function is 0, and it will approach 0 where the original function approaches infinity.
Remember to label your graphs clearly and indicate any points of discontinuity on the graph of the reciprocal function.
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The functionsย ๐ย andย โย are given byย ย ย ย ย ย ๐โก(๐ฅ)=log4โก(2โข๐ฅ)ย ย ย ย ย ย ย โโก(๐ฅ)=(๐๐ฅ)5๐(1/4).(i) Solveย ๐โก(๐ฅ)=3ย for values ofย ๐ฅย in the domain ofย ๐.
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