To fine the parameter values of the Bernoulli Distribution, we do not maximize the likelihood function but the:1 pointlog of the likelihood function the root mean square error
Question
To fine the parameter values of the Bernoulli Distribution, we do not maximize the likelihood function but the:1 pointlog of the likelihood function the root mean square error
Solution
To find the parameter values of the Bernoulli Distribution, we maximize the log of the likelihood function, not the root mean square error.
Here's a step-by-step explanation:
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The Bernoulli Distribution is a discrete probability distribution for a random variable which can take a binary, boolean output: 1 (success) or 0 (failure).
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The likelihood function for a Bernoulli Distribution is the product of the probabilities of each data point. For a set of data points, the likelihood function would be P^x * (1-P)^(n-x), where P is the probability of success, n is the total number of trials, and x is the number of successes.
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However, when we have a lot of data points, the likelihood function can become very small and difficult to work with. To make it easier, we take the natural logarithm of the likelihood function. This is called the log-likelihood function.
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The log-likelihood function for a Bernoulli Distribution is x*log(P) + (n-x)*log(1-P).
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We then find the value of P that maximizes this log-likelihood function. This is done by taking the derivative of the log-likelihood function with respect to P, setting it to zero, and solving for P.
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The root mean square error is not involved in this process. It is a measure of the differences between values predicted by a model and the values actually observed, but it is not used to find the parameter values of a Bernoulli Distribution.
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