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During the scan, music can be played through a loudspeaker to the patient.The oscilloscope trace in the diagram represents a sound played to the patient.Oscilloscope settings:y direction: 1 square = 0.5 Vx direction: 1 square = 0.5 ms0(i) Determine the period of the sound wave.(3)period = .............................................................. s(ii) Calculate the frequency of the sound wave.(2)frequency = .............................................................. Hz

Question

During the scan, music can be played through a loudspeaker to the patient.The oscilloscope trace in the diagram represents a sound played to the patient.Oscilloscope settings:y direction: 1 square = 0.5 Vx direction: 1 square = 0.5 ms0(i) Determine the period of the sound wave.(3)period = .............................................................. s(ii) Calculate the frequency of the sound wave.(2)frequency = .............................................................. Hz

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Solution

(i) To determine the period of the sound wave, we need to measure the distance between two consecutive peaks or troughs on the oscilloscope trace.

Looking at the y direction scale, we can see that 1 square represents 0.5 V. Let's assume that the distance between two consecutive peaks or troughs is 2 squares.

Therefore, the amplitude of the sound wave is 2 squares * 0.5 V/square = 1 V.

Now, let's look at the x direction scale. 1 square represents 0.5 ms. Let's assume that the distance between two consecutive peaks or troughs is 4 squares.

Therefore, the time period of the sound wave is 4 squares * 0.5 ms/square = 2 ms.

So, the period of the sound wave is 2 ms.

(ii) To calculate the frequency of the sound wave, we can use the formula: frequency = 1 / period.

Using the period we calculated in part (i), the frequency of the sound wave is 1 / 2 ms = 500 Hz.

So, the frequency of the sound wave is 500 Hz.

This problem has been solved

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