To find the volume of the solid formed by rotating the region bounded by the curves y = -x^2 + 6x - 8 and y = 0 about the x-axis, we can use the disk method.

The disk method formula is V = π ∫ [R(x)]^2 dx from a to b, where R(x) is the radius of the disk at x and [a, b] is the interval over which we integrate.

Here, the radius R(x) of the disk at x is the distance from the x-axis to the curve y = -x^2 + 6x - 8, which is simply the value of y at x. So, R(x) = -x^2 + 6x - 8.

We need to find the points where the curve

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To find the volume of the solid formed by rotating the region bounded by the curves y = -x^2 + 6x - 8 and y = 0 about the x-axis, we can use the disk method.

The disk method formula is V = π ∫ [R(x)]^2 dx from a to b, where R(x) is the radius of the disk at x and [a, b] is the interval over which we integrate.

Here, the radius R(x) of the disk at x is the distance from the x-axis to the curve y = -x^2 + 6x - 8, which is simply the value of y at x. So, R(x) = -x^2 + 6x - 8.

We need to find the points where the curve

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To find the volume of the solid formed by rotating the region bounded by the curves y = -x^2 + 6x - 8 and y = 0 about the x-axis, we can use the disk method.

The disk method formula is V = π ∫ [R(x)]^2 dx from a to b, where R(x) is the radius of the disk at x and [a, b] is the interval over which we integrate.

Here, the radius R(x) of the disk at x is the distance from the x-axis to the curve y = -x^2 + 6x - 8, which is simply the value of y at x. So, R(x) = -x^2 + 6x - 8.

We need to find the points where the curve

The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any method.y = −x2 + 6x − 8, y = 0; about the x-axisV =

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