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25 numbers were recorded and their average was calculated as 50.6. Later it was found that three numbers 29, 35, and 72 were wrongly taken as 92, 53 and 27 respectively, and one number 58 was inadvertently left out from being recorded. What is the correct average of all the numbers?

Question

25 numbers were recorded and their average was calculated as 50.6. Later it was found that three numbers 29, 35, and 72 were wrongly taken as 92, 53 and 27 respectively, and one number 58 was inadvertently left out from being recorded. What is the correct average of all the numbers?

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Solution

Step 1: Calculate the sum of the original 25 numbers. This can be done by multiplying the average by the number of values. So, 50.6 * 25 = 1265.

Step 2: Calculate the sum of the wrongly recorded numbers. This is 92 + 53 + 27 = 172.

Step 3: Calculate the sum of the correct numbers that should have been recorded. This is 29 + 35 + 72 = 136.

Step 4: Calculate the difference between the sum of the wrongly recorded numbers and the correct numbers. This is 172 - 136 = 36.

Step 5: Subtract this difference from the original sum of the 25 numbers. This gives the corrected sum of the 25 numbers. So, 1265 - 36 = 1229.

Step 6: Add the number that was left out (58) to the corrected sum of the 25 numbers. This gives the total sum of all the numbers. So, 1229 + 58 = 1287.

Step 7: The correct average of all the numbers is the total sum divided by the total number of values. The total number of values is the original 25 plus the one that was left out, so 26. Therefore, the correct average is 1287 / 26 = 49.5.

This problem has been solved

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