Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of nitrogen monoxide produced by the reaction of 0.10mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Question
Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of nitrogen monoxide produced by the reaction of 0.10mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Solution
The balanced chemical equation for the reaction is:
4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)
From the balanced equation, we can see that 5 moles of oxygen (O2) react to produce 4 moles of nitrogen monoxide (NO).
Therefore, the ratio of moles of O2 to moles of NO is 5:4.
So, if we have 0.10 moles of O2, we can calculate the moles of NO produced as follows:
(0.10 moles O2) * (4 moles NO / 5 moles O2) = 0.08 moles NO
So, 0.10 moles of oxygen will produce approximately 0.08 moles of nitrogen monoxide.
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