Question 2: For a given list of strings, please create a new list where each element is the uppercase version of the first letter of a string with a length greater than or equal to 5 in the original list.words = ["apple", "banana", "orange", "mango", "kiwi", "pear"]

Create a list b with elements 'apple', 'banana', 'cherry', and concatenate them into a single string using a space as a separator. Count the occurrences of the word 'is' in the string a. Create a dictionary d with word frequencies from the list b.

Question 3: Given a list of cities, create a new list where each element is a tuple containing the city name and its length.cities = ["New York", "London", "Tokyo", "Paris", "Sydney"]

Match the words in List I with their meanings in List IIChoose the correct answer from the options given below:

Write a function top5_words(text) that takes a single argument text (a non-empty string), tokenises text into words based on whitespace (once again, without any stripping of punctuation or case normalisation), and returns the top-5 words as a list of strings, in descending order of frequency. If there is a tie in frequency at any point, the words with the same frequency should be sub-sorted alphabetically (e.g. if 'turtle' and 'grok' both occur 5 times, 'grok' should come first). If there are less than five distinct words in text, the function should return all words in descending order of frequency (with the same tie-breaking mechanism). For example:>>> top5_words("one one was a racehorse two two was one too")["one", "two", "was", "a", "racehorse"]>>> top5_words("buffalo buffalo buffalo chicken buffalo")["buffalo", "chicken"]>>> top5_words("the quick brown fox jumped over the lazy dog")["the", "brown", "dog", "fox", "jumped"]

Define a function first_word(arg1),with a string argument arg1. In the function:a. use split() function to separate arg1 by "," into a list of wordsb. Return res that is the last element of the list of words