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A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform currentdensity of 2.8 × 107 A/m2 . The current is:A. 0.63 A2B. 2.0 AC. 5.9 A2D. 296 AE. 400 A2

Question

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform currentdensity of 2.8 × 107 A/m2 . The current is:A. 0.63 A2B. 2.0 AC. 5.9 A2D. 296 AE. 400 A2

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Solution

The current in a wire can be calculated using the formula:

I = J * A

where: I is the current, J is the current density, and A is the cross-sectional area of the wire.

The cross-sectional area of a wire can be calculated using the formula for the area of a circle:

A = πr²

where: A is the area, and r is the radius of the wire.

Given: J = 2.8 × 10^7 A/m² r = 0.15 mm = 0.15 * 10^-3 m (since 1 mm = 10^-3 m)

We can first calculate the cross-sectional area of the wire:

A = π * (0.15 * 10^-3 m)² = 0.0000707 m²

Then, we can calculate the current:

I = J * A = 2.8 × 10^7 A/m² * 0.0000707 m² = 1.98 A

So, the current in the wire is approximately 2.0 A. Therefore, the correct answer is B. 2.0 A.

This problem has been solved

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