What is the output of the following code snippet?class Node: def __init__(self, value): self.data = value self.left = None self.right = Nonedef calculate_sum(node): if node is None: return 0 return node.data + calculate_sum(node.left) + calculate_sum(node.right) # Usage example:root = Node(1)root.left = Node(2)root.right = Node(3)root.left.left = Node(4)root.left.right = Node(5)print(calculate_sum(root))Options615110
Question
What is the output of the following code snippet?class Node: def init(self, value): self.data = value self.left = None self.right = Nonedef calculate_sum(node): if node is None: return 0 return node.data + calculate_sum(node.left) + calculate_sum(node.right) # Usage example:root = Node(1)root.left = Node(2)root.right = Node(3)root.left.left = Node(4)root.left.right = Node(5)print(calculate_sum(root))Options615110
Solution
The output of the given code snippet will be 15.
Here's how:
The calculate_sum function is a recursive function that sums up the values of a binary tree. It starts at the root node and then recursively adds the value of the left child and the right child.
The binary tree in the usage example is structured like this:
1
/ \
2 3
/ \
4 5
So, the sum is calculated as follows:
1 (value of root) + 2 (value of root.left) + 3 (value of root.right) + 4 (value of root.left.left) + 5 (value of root.left.right) = 15.
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