Knowee
Questions
Features
Study Tools

Suppose the decomposition of ozone proceeds by the following mechanism:step elementary reaction rate constant1 O3(g) → O2(g) + O(g) k12 O3(g) + O(g) → 2O2(g) k2Suppose also k1≫k2. That is, the first step is much faster than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k

Question

Suppose the decomposition of ozone proceeds by the following mechanism:step elementary reaction rate constant1 O3(g) → O2(g) + O(g) k12 O3(g) + O(g) → 2O2(g) k2Suppose also k1≫k2. That is, the first step is much faster than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The balanced chemical equation for the overall chemical reaction is:

2O3(g) → 3O2(g)

The experimentally-observable rate law for the overall chemical reaction is:

rate = k[O3]^2

This is because the overall reaction is second order with respect to O3.

The rate constant k for the overall chemical reaction cannot be expressed simply in terms of k1 and k2. This is because the rate constant for the overall reaction depends on the mechanism of the reaction, which includes the relative rates of the elementary steps and possible reverse reactions. However, if we assume that the first step is at equilibrium (because it is much faster than the second step), then we can express the rate constant for the overall reaction as:

k = k1 * k2 / (k-1 + k2)

where k-1 is the rate constant for the reverse of the first elementary reaction. This expression assumes that the reverse of the second elementary reaction is negligible, which may or may not be a good assumption depending on the specific system.

This problem has been solved

Similar Questions

Suppose the reaction between nitric oxide and oxygen proceeds by the following mechanism:step elementary reaction rate constant1 NO(g) + O2(g) → NO2(g) + O(g) k12 NO(g) + O(g) → NO2(g) k2Suppose also k1≫k2. That is, the first step is much faster than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k

Suppose the decomposition of nitrogen dioxide proceeds by the following mechanism:step elementary reaction rate constant1 NO2(g) → NO(g) + O(g) k12 O(g) + NO2(g) → O2(g) + NO(g) k2Suppose also k1≪k2. That is, the first step is much slower than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k

Suppose the decomposition of dinitrogen monoxide proceeds by the following mechanism:step elementary reaction rate constant1 N2O(g) → N2(g) + O(g) k12 N2O(g) + O(g) → N2(g) + O2(g) k2Suppose also k1≪k2. That is, the first step is much slower than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k

One mechanism for the destruction of ozone in the upper atomosphere is:Step 1: O3 (g) + NO (g) → NO2 (g) + O2 (g) [slow]Step 2: NO2 (g) + O (g) → NO (g) + O2 (g) [fast](a) Write the balanced overall reaction with state symbols. (1 point)(b) For the uncatalysed reaction, the activation energy is 14.0 kJ. The activation energy for thesame reaction when catalysed is 11.9 kJ. What is the ratio of the rate constant for the catalysedreaction to that for the uncatalysed reaction at 25 °C? Assume that the frequency factor A is thesame for each reaction and R to be 8.314 J/mol.K. (2 points)(c) One of the concerns about the use of Freons (CCl2F2) is that they will migrate to the upperatmosphere where chlorine atoms can be generated by the following reaction:CCl2F2 (g) ℎ𝑣→ CF2Cl (g) + Cl (g)Page 2 of 3RestrictedChlorine atoms can act as a catalyst in the destruction of ozone. The activation energy for thereactionCl (g) + O3 (g) → ClO (g) + O2 (g)is 2.1 kJ. Which is the more effective catalyst (Cl or NO) for the destruction of ozone? Explain.(1 point)(d) Compare the efficiency of Cl atom and NO molecules (by calculating the ratio of 𝑘Cl𝑘NO), assumingthat the frequency factor A is the same for each reaction. Show all working. (2 points)

Decomposition of H2O2 follows a first order reaction. In fifty minutes the concentration of H2O2 decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of H2O2 reaches 0.05 M, the rate of formation of O2 will be:

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.