Problem StatementKabir is stuck in a maze of singly linked list where he can only move forward. But this contains a loop because of which Kabir is not able to come out. Help Kabir find out if there is a loop in the maze.Input FormatFirst line contains 1 integer t, denoting number of test cases.The next line of each test case contains an integer, index denoting the node number which has to be made the next node for the last node of the linked list. -1 means NULL pointer.The next line of each test case contains an integer n, denoting the number of nodes in the linked list.The next n lines of each test case contains tigers denoting the nodes of the linked list.Constraints1<=t<=1000<=list[i]<=1000Output FormatPrint 1 or 0 if he is able to find a loop or not.Sample Input1-111Sample Output0Explanationlist is 1->NULL, hence no loop

The problem statement is asking to determine if a singly linked list contains a loop. A singly linked list is a type of data structure where each element points to the next element in the list. A loop in a linked list occurs when the last element in the list points back to an earlier element instead of pointing to null.

Here are the steps to solve this problem:

1. Initialize two pointers, slow and fast, to the head of the linked list.
2. Move slow one step at a time and fast two steps at a time.
3. If there is a loop in the list, the fast pointer will eventually catch up to the slow pointer.
4. If the fast pointer reaches the end of the list (i.e., it becomes null), then there is no loop in the list.
5. Return 1 if there is a loop and 0 if there is no loop.

This algorithm is known as Floyd's Cycle-Finding Algorithm and it works because if there is a loop, the fast pointer will eventually enter the loop and catch up to the slow pointer. If there is no loop, the fast pointer will reach the end of the list.

The problem statement is asking to determine if a singly linked list contains a loop. A singly linked list is a type of data structure that contains nodes, where each node points to the next node in the list. A loop in a linked list occurs when a node points back to a previous node in the list, causing an infinite loop.

Here are the steps to solve this problem:

1. Initialize two pointers, slow and fast, at the head of the linked list.
2. Move slow pointer by one node and fast pointer by two nodes in each iteration.
3. If there is a loop in the list, the fast pointer will eventually meet the slow pointer.
4. If the fast pointer reaches the end of the list (NULL), then there is no loop.

The input format is as follows:

• The first line contains an integer t, denoting the number of test cases.
• The next line of each test case contains an integer, index denoting the node number which has to be made the next node for the last node of the linked list. -1 means NULL pointer.
• The next line of each test case contains an integer n, denoting the number of nodes in the linked list.
• The next n lines of each test case contains integers denoting the nodes of the linked list.

The output format is as follows:

• Print 1 if there is a loop in the linked list.
• Print 0 if there is no loop in the linked list.

For example, if the input is: 1 -1 1 1

The output will be 0, because the list is 1->NULL, hence no loop.