If the temperature of the concentration cell increases, the magnitude of Ksp will:A.increase.B.decrease.C.equal zero.D.remain constant.
Question
If the temperature of the concentration cell increases, the magnitude of Ksp will:A.increase.B.decrease.C.equal zero.D.remain constant.
Solution
The answer is A. increase.
Here's the step by step explanation:
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The solubility product constant (Ksp) is a measure of how much a solid can dissolve in a liquid. It's determined by the concentrations of the ions in the solution at equilibrium.
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According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration of components, the system will shift its equilibrium position to counteract the effect of the disturbance.
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In the case of a concentration cell, if the temperature increases, the system will try to absorb the excess heat by shifting the reaction to the endothermic direction.
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The dissolution of most solids in water is an endothermic process, meaning it absorbs heat. Therefore, when the temperature increases, the equilibrium will shift to the right, towards the dissolved ions, to absorb the excess heat.
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As a result, more solid will dissolve, increasing the concentrations of the ions in the solution. This will increase the value of Ksp.
So, if the temperature of the concentration cell increases, the magnitude of Ksp will increase.
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