Factor completely.16t2–56t+49
Question
Factor completely.16t2–56t+49
Solution
Sure, here are the steps to factor the given expression completely:
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The given expression is 16t^2 - 56t + 49.
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First, we look for the greatest common factor (GCF). In this case, the GCF is 1.
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Next, we look at the expression in the form of ax^2 + bx + c. We need to find two numbers that multiply to give ac (which is 16*49 = 784) and add up to give b (which is -56).
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The two numbers that satisfy these conditions are -28 and -28 because -28*-28 = 784 and -28 + -28 = -56.
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We rewrite the middle term of the expression as the sum of the products of these two numbers and the variable t. So, the expression becomes 16t^2 - 28t - 28t + 49.
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Now, we group the terms to factor by grouping: (16t^2 - 28t) - (28t - 49).
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We factor out the GCF from each group: 4t(4t - 7) - 7(4t - 7).
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Now, we notice that (4t - 7) is a common factor in both terms, so we factor that out to get: (4t - 7)(4t - 7).
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Since (4t - 7)(4t - 7) is the same as (4t - 7)^2, the completely factored form of the expression is (4t - 7)^2.
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