A spends 20% of his monthly salary on house rent and 25% of the remaining monthly salary on travelling. He spends his remaining monthly salary on food and children's education in the ratio of 3:5 respectively. If the difference between the amount spent on children's education and house rent is Rs.700, then find the monthly salary of A (in Rs).
Question
A spends 20% of his monthly salary on house rent and 25% of the remaining monthly salary on travelling. He spends his remaining monthly salary on food and children's education in the ratio of 3:5 respectively. If the difference between the amount spent on children's education and house rent is Rs.700, then find the monthly salary of A (in Rs).
Solution
Let's assume the monthly salary of A is x Rs.
Step 1: Calculate the amount spent on house rent. A spends 20% of his monthly salary on house rent, so the amount spent on house rent is (20/100) * x = 0.2x Rs.
Step 2: Calculate the remaining monthly salary after paying house rent. The remaining monthly salary after paying house rent is x - 0.2x = 0.8x Rs.
Step 3: Calculate the amount spent on traveling. A spends 25% of the remaining monthly salary on traveling, so the amount spent on traveling is (25/100) * 0.8x = 0.2x Rs.
Step 4: Calculate the remaining monthly salary after paying for traveling. The remaining monthly salary after paying for traveling is 0.8x - 0.2x = 0.6x Rs.
Step 5: Calculate the ratio between the amount spent on food and children's education. The ratio between the amount spent on food and children's education is 3:5.
Step 6: Calculate the amount spent on children's education. Let's assume the amount spent on food is 3y Rs and the amount spent on children's education is 5y Rs.
Step 7: Calculate the difference between the amount spent on children's education and house rent. The difference between the amount spent on children's education and house rent is 5y - 0.2x = 700 Rs.
Step 8: Solve the equation to find the value of y. 5y - 0.2x = 700 5y = 0.2x + 700 y = (0.2x + 700)/5
Step 9: Substitute the value of y in the equation to find the monthly salary of A. 0.6x - 0.2x = 3y + 5y 0.4x = 8y 0.4x = 8((0.2x + 700)/5) 0.4x = (1.6x + 5600)/5 2x = 1.6x + 5600 0.4x = 5600 x = 5600/0.4
Therefore, the monthly salary of A is 14,000 Rs.
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