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Suppose that a pest control program is dealing with two types of rats, black and brown.It is found that the probability of a rat being brown, given that it is caught in a trap, is 0.27.It is estimated that the probability of any rat being caught is 0.37 and thatthe probability of a randomly chosen rat in the region being brown is 0.58.What is the probability of a rat being caught in a trap given that it is brown?

Question

Suppose that a pest control program is dealing with two types of rats, black and brown.It is found that the probability of a rat being brown, given that it is caught in a trap, is 0.27.It is estimated that the probability of any rat being caught is 0.37 and thatthe probability of a randomly chosen rat in the region being brown is 0.58.What is the probability of a rat being caught in a trap given that it is brown?

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Solution

To find the probability of a rat being caught in a trap given that it is brown, we can use Bayes' theorem. Bayes' theorem is a way to find a probability when we know certain other probabilities.

The formula is:

P(A|B) = P(B|A) * P(A) / P(B)

Where:

  • P(A|B) is the probability of event A happening given that event B is true.
  • P(B|A) is the probability of event B happening given that event A is true.
  • P(A) and P(B) are the probabilities of events A and B respectively.

In this case, we want to find P(Caught|Brown), the probability of a rat being caught given that it is brown. We know that:

  • P(Brown|Caught) = 0.27, the probability of a rat being brown given that it is caught.
  • P(Caught) = 0.37, the probability of any rat being caught.
  • P(Brown) = 0.58, the probability of a randomly chosen rat being brown.

Substituting these into the formula gives:

P(Caught|Brown) = P(Brown|Caught) * P(Caught) / P(Brown) = 0.27 * 0.37 / 0.58 = 0.0999 / 0.58 = 0.1724 (rounded to four decimal places)

So, the probability of a rat being caught in a trap given that it is brown is approximately 0.1724 or 17.24%.

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