A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The reverse recovery current is given as 0.5A and the reverse recovery time is given as 100ns with the maximum reverse blocking voltage as 400V. The on-off switching loss is computed as: Select one:a. 2 Wb. 1 Wattc. 0.5 Wd. None of the given choices
Question
A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The reverse recovery current is given as 0.5A and the reverse recovery time is given as 100ns with the maximum reverse blocking voltage as 400V. The on-off switching loss is computed as: Select one:a. 2 Wb. 1 Wattc. 0.5 Wd. None of the given choices
Solution
The question is asking for the on-off switching loss of a Schottky diode in a power converter. Here are the steps to calculate it:
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First, we need to calculate the average current. The peak-to-peak current is 20A, and the duty cycle is 60%. Therefore, the average current is 20A * 60% = 12A.
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Next, we calculate the power loss during the on-state. The forward voltage drop (Vf) is 0.3V, so the power loss during the on-state is Vf * average current = 0.3V * 12A = 3.6W.
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Then, we calculate the power loss during the off-state. The reverse recovery current is 0.5A and the reverse recovery time is 100ns. Therefore, the power loss during the off-state is reverse recovery current * reverse recovery time = 0.5A * 100ns = 50µW.
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Finally, we add the on-state and off-state power losses to get the total power loss. However, the Schottky diode does not have a reverse recovery time, so the power loss during the off-state is 0. Therefore, the total power loss is 3.6W + 0 = 3.6W.
None of the given choices (2W, 1W, 0.5W) match this result, so the correct answer is d. None of the given choices.
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