To calculate the molarity of the solution, we can use the formula for osmotic pressure:

Π = n/V * R * T

where:
Π is the osmotic pressure,
n is the number of moles of the solute,
V is the volume of the solution in liters,
R is the ideal gas constant, and
T is the temperature in Kelvin.

Given:
Π = 13.3 kPa = 13.3 * 10^3 Pa (since 1 kPa = 10^3 Pa)
T = 21°C = 21 + 273.15 = 294.15 K (since Kelvin = Celsius + 273.15)
R = 8.314 Pa.m^3/mol.K (ideal gas constant)

We need to find n/V which is the molarity (M) of the solution.

Rearranging the formula for M gives:

M = Π / (R * T)

Substituting the given values:

M = 13.3 * 10^3 / (8.314 * 294.15)

Calculating this gives:

M ≈ 0.005 M

So, the molarity of the solution is approximately 0.005 M.

Question

To calculate the molarity of the solution, we can use the formula for osmotic pressure:

Π = n/V * R * T

where:
Π is the osmotic pressure,
n is the number of moles of the solute,
V is the volume of the solution in liters,
R is the ideal gas constant, and
T is the temperature in Kelvin.

Given:
Π = 13.3 kPa = 13.3 * 10^3 Pa (since 1 kPa = 10^3 Pa)
T = 21°C = 21 + 273.15 = 294.15 K (since Kelvin = Celsius + 273.15)
R = 8.314 Pa.m^3/mol.K (ideal gas constant)

We need to find n/V which is the molarity (M) of the solution.

Rearranging the formula for M gives:

M = Π / (R * T)

Substituting the given values:

M = 13.3 * 10^3 / (8.314 * 294.15)

Calculating this gives:

M ≈ 0.005 M

So, the molarity of the solution is approximately 0.005 M.

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