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What will be the output of the program? int i = 1, j = 10; do { if(i > j) { break; } j--; } while (++i < 5); System.out.println("i = " + i + " and j = " + j); i = 6 and j = 5 i = 5 and j = 5 i = 6 and j = 6 i = 5 and j = 6

Question

What will be the output of the program?

int i = 1, j = 10; do { if(i > j) { break; } j--; } while (++i < 5); System.out.println("i = " + i + " and j = " + j);

i = 6 and j = 5

i = 5 and j = 5

i = 6 and j = 6

i = 5 and j = 6

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Solution

The output of the program will be "i = 5 and j = 6".

Here's the step by step explanation:

  1. The initial values are i = 1 and j = 10.
  2. The do-while loop starts. The condition inside the loop is if i > j, then break. But at the start, i is not greater than j, so it doesn't break and goes to the next line.
  3. j is decremented by 1, so now j = 9.
  4. At the end of the loop, i is incremented by 1 (due to ++i), so now i = 2.
  5. The loop condition is checked (i < 5), which is true, so the loop runs again.
  6. This process continues until i = 5 and j = 6. At this point, when the loop tries to run again, the condition (i < 5) is false, so the loop ends.
  7. The final values of i and j are printed, which are i = 5 and j = 6.

This problem has been solved

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