A 0.016 kg record with a radius of 15 cm rotates with an angular speed of 28 rpm. Find the angular momentum of the record.
Question
A 0.016 kg record with a radius of 15 cm rotates with an angular speed of 28 rpm. Find the angular momentum of the record.
Solution
Sure, here are the steps to find the angular momentum of the record:
Step 1: Convert the angular speed from revolutions per minute (rpm) to radians per second.
1 revolution = 2π radians, and 1 minute = 60 seconds.
So, 28 rpm = 28 * 2π / 60 rad/s ≈ 2.93 rad/s.
Step 2: The moment of inertia (I) for a disk is given by the formula I = 0.5 * m * r^2, where m is the mass and r is the radius.
Substitute the given values into the formula: I = 0.5 * 0.016 kg * (0.15 m)^2 ≈ 0.00018 kg*m^2.
Step 3: The angular momentum (L) is given by the formula L = I * ω, where I is the moment of inertia and ω is the angular speed.
Substitute the values from steps 1 and 2 into this formula: L = 0.00018 kgm^2 * 2.93 rad/s ≈ 0.00053 kgm^2/s.
So, the angular momentum of the record is approximately 0.00053 kg*m^2/s.
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