To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance
N0 is the initial amount of the substance
t is the time that has passed
T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains. We know that t = 4.63103 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(4.63103/1600)

Calculating this gives us:

N/N0 = 0.9971

To express this as a percentage, we multiply by 100, which gives us 99.71%. However, the problem asks us to round our answer to two significant digits, so our final answer is 100%.

Question

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance
N0 is the initial amount of the substance
t is the time that has passed
T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains. We know that t = 4.63103 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(4.63103/1600)

Calculating this gives us:

N/N0 = 0.9971

To express this as a percentage, we multiply by 100, which gives us 99.71%. However, the problem asks us to round our answer to two significant digits, so our final answer is 100%.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance
N0 is the initial amount of the substance
t is the time that has passed
T is the half-life of the substance

In this case, we want to find N/N0, which is the fraction of the substance that remains. We know that t = 4.63103 years and T = 1600 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(4.63103/1600)

Calculating this gives us:

N/N0 = 0.9971

To express this as a percentage, we multiply by 100, which gives us 99.71%. However, the problem asks us to round our answer to two significant digits, so our final answer is 100%.

Radium-226 is radioactive and has a half life of 1600. years. What percentage of a sample would be left after ×4.63103 years?Round your answer to 2 significant digits.

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