Precise measurements give the following masses:nuclide mass23994Pu 239.0522u42He 4.00260u24296Cm 242.0588uparticle mass10n 1.0086649u0−1e ×5.485810−4u01e ×5.485810−4uNow consider the following nuclear reaction:→+23994Pu  42He + 24296Cm  10nIs energy released or absorbed by this reaction? releasedabsorbedneither releasednor absorbedI need moreinformation to decide.If you said energy was released or absorbed, calculate how much energy is released or absorbed.kJ/molGive your answer in both kJ/mol and MeV. Be sure each of your answer entries has the correct number of significant digits.Note: take particular care to keep enough digits in any intermediate calculation, and use enough digits in any scientific constants you need, since the data with which you are working are very precise. MeV

To determine whether energy is released or absorbed in this nuclear reaction, we need to calculate the mass difference before and after the reaction. This is based on the principle of mass-energy equivalence, which states that mass can be converted into energy and vice versa.

The mass before the reaction is the sum of the masses of 23994Pu and 42He, which is 239.0522u + 4.00260u = 243.0548u.

The mass after the reaction is the sum of the masses of 24296Cm and 10n, which is 242.0588u + 1.0086649u = 243.0674649u.

The mass difference is 243.0674649u - 243.0548u = 0.0126649u.

According to the principle of mass-energy equivalence, this mass difference corresponds to the energy released or absorbed by the reaction. The conversion factor between atomic mass units (u) and energy is 931.5 MeV/u, so the energy corresponding to the mass difference is 0.0126649u * 931.5 MeV/u = 11.8 MeV.

To convert this energy to kJ/mol, we use the conversion factors 1 MeV = 1.60218 x 10^-13 kJ and 1 mol = 6.022 x 10^23 particles. Therefore, the energy in kJ/mol is 11.8 MeV * 1.60218 x 10^-13 kJ/MeV * 6.022 x 10^23 mol = 1.13 x 10^6 kJ/mol.

Therefore, energy is released by this reaction, and the amount of energy released is 11.8 MeV or 1.13 x 10^6 kJ/mol.