Which would be the first term of the given sequence that would be a multiple of 3: 68, 65, 62, 59 .... ?

The given sequence is a decreasing arithmetic sequence, where each term is 3 less than the previous term.

To find the first term that is a multiple of 3, we need to find a term in the sequence that can be divided by 3 with no remainder.

Starting with the first term, 68, we can see that it is not a multiple of 3.

The next term, 65, is also not a multiple of 3.

The third term, 62, is not a multiple of 3 either.

The fourth term, 59, is not a multiple of 3.

We continue this process until we find a term that is a multiple of 3.

The first term that is a multiple of 3 is 57.

So, the first term of the given sequence that would be a multiple of 3 is 57.