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At a pizza shop, 80% of the customers order a pizza, 15% of the customers order a salad, and 10% of the customers order both a pizza and a salad.If a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?A.0.65B.0.12C.0.95D.0.85

Question

At a pizza shop, 80% of the customers order a pizza, 15% of the customers order a salad, and 10% of the customers order both a pizza and a salad.If a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?A.0.65B.0.12C.0.95D.0.85

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Solution

The probability of a customer ordering either a pizza or a salad can be found by adding the probability of a customer ordering a pizza to the probability of a customer ordering a salad, and then subtracting the probability of a customer ordering both.

The probability of a customer ordering a pizza is 0.80 (or 80%), the probability of a customer ordering a salad is 0.15 (or 15%), and the probability of a customer ordering both is 0.10 (or 10%).

So, the probability of a customer ordering either a pizza or a salad is 0.80 + 0.15 - 0.10 = 0.85 (or 85%).

Therefore, the answer is D. 0.85.

This problem has been solved

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