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Four vehicles approach an intersection with a 4 way stop at the same time. Car B is ahead of Car A and both are in the same lane and want to proceed straight across. Car C is across the intersection from Car B and wants to proceed straight as well. Car D is to the right of Car B and wants to make a right turn. Which car must yield?

Question

Four vehicles approach an intersection with a 4 way stop at the same time. Car B is ahead of Car A and both are in the same lane and want to proceed straight across. Car C is across the intersection from Car B and wants to proceed straight as well. Car D is to the right of Car B and wants to make a right turn. Which car must yield?

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Solution

The rules for a 4-way stop are generally that the first vehicle to arrive at the intersection has the right of way. If two vehicles arrive at the same time, the vehicle on the right has the right of way. If vehicles arrive at the same time across from each other, the one going straight has the right of way.

In this scenario, all four cars arrive at the same time.

  1. Car B and Car A are in the same lane. Since Car B is ahead of Car A, Car B goes first.

  2. Car C is across the intersection from Car B. Since both want to proceed straight, they can do so at the same time because they are not crossing paths.

  3. Car D is to the right of Car B and wants to make a right turn. Car D can proceed after Car B and Car C have moved as it is not crossing any of their paths.

So, Car A must yield until Car B, Car C, and Car D have proceeded.

This problem has been solved

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