Two particles of equal mass go round a circle of radius under the action of their mutualgravitational attraction. The speed of each particle is
Question
Two particles of equal mass go round a circle of radius under the action of their mutualgravitational attraction. The speed of each particle is
Solution
The speed of each particle can be calculated using the formula for the gravitational force and centripetal force.
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First, we know that the gravitational force between two objects is given by F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
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We also know that the centripetal force required to keep an object moving in a circle is given by F = m * v^2 / r, where m is the mass of the object, v is its speed, and r is the radius of the circle.
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Since the gravitational force is providing the centripetal force, we can set these two equations equal to each other and solve for v:
G * (m * m) / r^2 = m * v^2 / r
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Simplifying this equation gives us v^2 = G * m / r.
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Taking the square root of both sides gives us the speed of each particle: v = sqrt(G * m / r).
Please note that the value of G (gravitational constant) is approximately 6.674 * 10^-11 N(m/kg)^2, m is the mass of the particle, and r is the radius of the circle.
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