Consider that a computer system has a 32-bit address space, which means that it can address up to 2^32 memory locations. The system also has a paging mechanism, where each page frame is 4 KB in size.If the kernel occupies 16 MB of memory, how many page frames does it occupy?Answer( Please choose a correct answer ) CLEAR4096.04254.08192.016384.0
Question
Consider that a computer system has a 32-bit address space, which means that it can address up to 2^32 memory locations. The system also has a paging mechanism, where each page frame is 4 KB in size.If the kernel occupies 16 MB of memory, how many page frames does it occupy?Answer( Please choose a correct answer ) CLEAR4096.04254.08192.016384.0
Solution
To solve this problem, we first need to understand that 1 KB (kilobyte) is equal to 1024 bytes, and 1 MB (megabyte) is equal to 1024 KB.
Given that the kernel occupies 16 MB of memory, we first convert this to KB:
16 MB * 1024 KB/MB = 16384 KB
Next, we know that each page frame is 4 KB in size. So, we divide the total size of the kernel by the size of each page frame to find out how many page frames the kernel occupies:
16384 KB / 4 KB/page frame = 4096 page frames
So, the kernel occupies 4096 page frames.
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