How many moles of OH− are there in 2.999 g of Mg(OH)2?Give your answer in moles and to three decimal places.(Molar mass of Mg(OH)2 = 58.32 g mol−1)
Question
How many moles of OH− are there in 2.999 g of Mg(OH)2?Give your answer in moles and to three decimal places.(Molar mass of Mg(OH)2 = 58.32 g mol−1)
Solution
To find the number of moles in a given mass of a substance, you can use the formula:
Number of moles = mass of substance / molar mass of substance
Given: Mass of Mg(OH)2 = 2.999 g Molar mass of Mg(OH)2 = 58.32 g/mol
Substitute the given values into the formula:
Number of moles of Mg(OH)2 = 2.999 g / 58.32 g/mol = 0.051 moles
However, each formula unit of Mg(OH)2 contains two OH- ions. Therefore, the number of moles of OH- is twice the number of moles of Mg(OH)2.
Number of moles of OH- = 2 * 0.051 moles = 0.102 moles
So, there are 0.102 moles of OH- in 2.999 g of Mg(OH)2.
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