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The probability of an earthquake incident at a mine site in a single year is 0.64.Consider a particular mine site X where 26 employees work 12 hours/day, 321 days/year in the pit and are therefore in the exposure zone of the incident. For people in the exposure zone there is a 0.10 probability that an earthquake incident will result in injury.What is the probability that there is injury from earthquake on that site in a year?Enter your answer to 3

Question

The probability of an earthquake incident at a mine site in a single year is 0.64.Consider a particular mine site X where 26 employees work 12 hours/day, 321 days/year in the pit and are therefore in the exposure zone of the incident. For people in the exposure zone there is a 0.10 probability that an earthquake incident will result in injury.What is the probability that there is injury from earthquake on that site in a year?Enter your answer to 3

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Solution

To calculate the probability of an injury from an earthquake at the mine site in a year, we need to multiply the probability of an earthquake occurring by the probability of that earthquake causing an injury.

The probability of an earthquake in a year is given as 0.64. The probability of an earthquake causing an injury is given as 0.10.

So, the probability of an injury from an earthquake in a year is 0.64 * 0.10 = 0.064 or 6.4%.

This problem has been solved

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