You hold a barbell in a horizontal position. The barbell’s center of mass (and thus gravity) is exactly midway between your two hands. A friend walks up and attaches a weight on the end near your left hand. How does the torque on the bar exerted by your left hand compare to the torque on the bar from your right hand, assuming that the bar remains horizontal and at rest? Group of answer choicesMore information is needed to answer.The torque from the left hand is less than the torque from the right hand.The torque from the left hand is equal to the torque from the right hand.The torque from the left hand is greater than the torque from the right hand.
Question
You hold a barbell in a horizontal position. The barbell’s center of mass (and thus gravity) is exactly midway between your two hands. A friend walks up and attaches a weight on the end near your left hand. How does the torque on the bar exerted by your left hand compare to the torque on the bar from your right hand, assuming that the bar remains horizontal and at rest? Group of answer choicesMore information is needed to answer.The torque from the left hand is less than the torque from the right hand.The torque from the left hand is equal to the torque from the right hand.The torque from the left hand is greater than the torque from the right hand.
Solution
The torque from the left hand is greater than the torque from the right hand.
Here's why:
Torque is the rotational equivalent of force and is calculated as the product of the force applied and the distance from the pivot point (in this case, the center of mass of the barbell). When the weight is added to the left end of the barbell, the left hand must exert more force to keep the barbell horizontal and at rest. This increased force, multiplied by the distance from the center of mass, results in a greater torque exerted by the left hand compared to the right hand.
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