Given vector A=5.00i - 8.00j . What is the direction of vector A?Group of answer choices30o South of East60o South of East30o North of East60o North of West

The direction of a vector is found using the tangent of the angle it makes with the positive x-axis (East direction). The tangent of the angle (θ) is given by the ratio of the y-component to the x-component of the vector.

In this case, vector A = 5.00i - 8.00j. Here, i is the x-component (East-West direction) and j is the y-component (North-South direction).

So, tan(θ) = -8.00 / 5.00 = -1.60.

To find the angle, we take the inverse tangent (also known as arctan or tan^-1) of -1.60.

θ = arctan(-1.60) = -58.0 degrees.

The negative sign indicates that the direction is below the x-axis.

So, the direction of vector A is 58.0 degrees South of East.

However, this is not one of the options given. The closest option is 60 degrees South of East. So, the answer is 60 degrees South of East.