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How much would $200 invested at 5% interest compounded monthly be worth after 9 years? Round your answer to the nearest cent.𝐴(𝑡)=𝑃(1+𝑟𝑛)𝑛𝑡A(t)=P(1+ nr​ ) nt A.$313.37B.$310.27C.$207.63D.$363.82SUBMITarrow_backPREVIOUS

Question

How much would 200investedat5200 invested at 5% interest compounded monthly be worth after 9 years? Round your answer to the nearest cent.𝐴(𝑡)=𝑃(1+𝑟𝑛)𝑛𝑡A(t)=P(1+ nr​ ) nt A.313.37B.310.27C.310.27C.207.63D.$363.82SUBMITarrow_backPREVIOUS

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Solution

Para resolver esta pregunta, utilizaremos la fórmula del interés compuesto:

A(t)=P(1+rn)nt A(t) = P \left(1 + \frac{r}{n}\right)^{nt}

Donde:

  • P P es el monto principal (inicial), que es $200.
  • r r es la tasa de interés anual, que es 5% o 0.05.
  • n n es el número de veces que se compone el interés por año, que es 12 (mensualmente).
  • t t es el número de años, que es 9.

Sustituyendo estos valores en la fórmula:

A(9)=200(1+0.0512)129 A(9) = 200 \left(1 + \frac{0.05}{12}\right)^{12 \cdot 9}

Primero, calculamos el término dentro del paréntesis:

1+0.0512=1+0.0041667=1.0041667 1 + \frac{0.05}{12} = 1 + 0.0041667 = 1.0041667

Luego, elevamos este resultado a la potencia de 129 12 \cdot 9 :

1.00416671081.551328 1.0041667^{108} \approx 1.551328

Finalmente, multiplicamos este resultado por el monto principal:

A(9)=200×1.551328310.27 A(9) = 200 \times 1.551328 \approx 310.27

Por lo tanto, la respuesta correcta es:

B. $310.27

This problem has been solved

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