onsider XYZ in the figure below.The perpendicular bisectors of its sides are TS, US, and VS. They meet at a single point S.(In other words, S is the circumcenter of XYZ.)Suppose =VS72, =YZ80, and =ZS120.Find XS, UZ, and VY.

Consider TUV in the figure below.The perpendicular bisectors of its sides are AD, BD, and CD. They meet at a single point D.(In other words, D is the circumcenter of TUV.)Suppose =CD30, =UV142, and =UD78.Find BV, VD, and TC.

Consider GHJ in the figure below.The perpendicular bisectors of its sides are KN, LN, and MN. They meet at a single point N.(In other words, N is the circumcenter of GHJ.)Suppose =LN48, =GK88, and =GN102.Find HN, LJ, and GJ.

Perpendicular bisector passes through the Blank 1 Question 14 of the given segment.

The angle bisectors of XYZ are XG, YG, and ZG. They meet at a single point G.(In other words, G is the incenter of XYZ.)Suppose =DG14, =XG19, =m∠DXF94°, and =m∠FZG16°.Find the following measures.

X and Y are centres of circles of radii 9 cm and 2 cm respectively, XY = 17 cm. Z is the centre of a circle of radius r cm which touches the above circles externally. Given that angle(XZY) = 90 deg, the value of r isChoices:- 6 CM 8 CM 9 CM 13 CM