The volume of a 500 g sealed packet is 350 cm3 . Will the packet float or sink in water if the density of water is 1 g cm–3? What will be the mass of the water displaced by this packet?
Question
The volume of a 500 g sealed packet is 350 cm3 . Will the packet float or sink in water if the density of water is 1 g cm–3? What will be the mass of the water displaced by this packet?
Solution
First, we need to calculate the density of the packet. Density is defined as mass divided by volume.
Given: Mass (m) = 500 g Volume (V) = 350 cm³
So, Density (D) = m/V = 500 g / 350 cm³ = 1.43 g/cm³
The density of the packet is greater than the density of water (1 g/cm³). Therefore, the packet will sink in water because objects with a density greater than the fluid they are in will sink.
The mass of the water displaced by the packet is equal to the volume of the packet multiplied by the density of water (since density = mass/volume, therefore mass = density x volume).
So, Mass of water displaced = Volume of packet x Density of water = 350 cm³ x 1 g/cm³ = 350 g.
So, the mass of the water displaced by the packet is 350 g.
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