Consider the following data: Class Interval: 0-10 10-20 20-30 30-40 40-50 50-60 60-70Frequency: 3, 5, 1, 2, 4, 3, 2The range of the above data is:a.0b.10c.60d.70Clear my choiceQuestion 2Not yet answeredMarked out of 3.00Flag questionQuestion textThe value of the first quartile is:a.10b.12c.14d.20
Question
Consider the following data: Class Interval: 0-10 10-20 20-30 30-40 40-50 50-60 60-70Frequency: 3, 5, 1, 2, 4, 3, 2The range of the above data is:a.0b.10c.60d.70Clear my choiceQuestion 2Not yet answeredMarked out of 3.00Flag questionQuestion textThe value of the first quartile is:a.10b.12c.14d.20
Solution
Consider the given data:
Class Interval: 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Frequency: 3, 5, 1, 2, 4, 3, 2
To find the range of the data, we need to subtract the smallest value from the largest value. In this case, the smallest value is 0 and the largest value is 70. Therefore, the range is 70 - 0 = 70.
So, the correct answer is d. 70.
Moving on to the second question:
To find the first quartile, we need to divide the data into four equal parts. Since we have 7 data points, the first quartile will be the value at the 25th percentile.
To calculate the position of the first quartile, we use the formula: (25/100) * (n + 1), where n is the number of data points. In this case, n = 7.
(25/100) * (7 + 1) = (1/4) * 8 = 2
So, the first quartile is the value at the 2nd position, which is 10.
Therefore, the correct answer is a. 10.
Similar Questions
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How many quartiles are there in a dataset?a.Threeb.Fourc.Oned.Two
Look at the box plot shown below. What is the 1st Quartile (Q1) of the data set?
Next, find Q1.Recall that the first quartile, Q1, is the median of the lower half of the data. That is, the median of the data located below the Q2 position.Consider the ordered list of data values. The median, Q2, which was determined in the last step, has been underlined for clarity.3, 6, 6, 7, 8, 8, 9, 10, 11There are nine values in the whole data set, but there are only values to the left of the underlined median. The first quartile, Q1, will be equal to the median of these values.Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values.median = sum of middle two values2The middle two values of the lower half of the data set are 6 and .Now, calculate the first quartile. Q1.Q1 = 6 + 2 = 2 =
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